The amount values recorded in the table at Figure 1 are calculated at 95% alc/vol. This is because all the distillate that will emerge from the run will be 95% except for the last of the middle-run and the tails. So, 95% alc/vol makes an accurate enough assumption.
Once the still is loaded it's important to calculate how much alcohol at 95% is in the still so the table at Figure 1 can be initialized. The following are two examples of how the volume of 95% alcohol is calculated: one with 500-ml of feints; and, one with no feints:
(Vol feints in ml X % alc of feints) + (Vol mash in ml X % alc of mash) / .95
((500-ml X .91) + (21000-ml X .0775)) / .95 = 2192-ml of 95% alc
(Vol mash in ml X % alc of mash) / .95 = Vol of 95% alc in the still
The table at Figure 1 has been initialized with this value as an example. The example is for 21L of mash at 7.75% alcohol.
Was this article helpful?